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6 votes
6 votes

A magnetic disk has $100$ cylinders, each with $10$ tracks of $10$ sectors. If each sector contains $128$ bytes, what is the maximum capacity of the disk in kilobytes?

  1. $1,280,000$
  2. $1280$
  3. $1250$
  4. $128,000$
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3 Answers

7 votes
7 votes
$\underline{\textbf{Answer:}\Rightarrow}\;\mathbf{c.}$

Magnetic disk capacity $=100\times 10 \times 10 \times 128 \\= 1280000\;\text{Bytes}\\=\dfrac{12380000}{1024} \;\text{KB}\\= 1250\;\text{KB}$
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3 votes
3 votes

Magnetic disk has 100 cylinder. Each cylinder contains 10 tracks.

Each track contain 10 sector & each sector contains 128 B of data.

Total Capacity = (No. of cylinder) * (No. of track in each cylinder) * (No. of sector in each track) * (Capacity of each sector)

= 100 * 10 * 10 * 128 B = 1280000 B = (1280000 / 1024 ) KB = 1250 KB.

So, maximum capacity is 1250 KB.

2 votes
2 votes

Capacity of disk= # of cylinder $*$ # of tracks/cylinder $*$ # of sector/track $*$ # of bytes/sector

$C= 100*10*10*128=1280000 B$

$C=1280000/1024 = 1250 KB$

Option c) is correct

Answer:

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