0 votes 0 votes Consider the function f(x) = x2 - 2x - 1. Suppose an execution of the Newton-Raphson method to find a zero of f(x) starts with an approximation x0 = 2 of x. What is the value of x2, the approximation of x that algorithm produces after two iterations, rounded to three decimal places? 2.417 2.419 2.423 2.425 IS&Software Engineering gateit-2008 numerical-methods newton-raphson normal + – Ishrat Jahan asked Oct 28, 2014 Ishrat Jahan 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes In newton method, if current guess is xcur, then new guess xnew is xnew = xcur - f(xcur)/f'(xcur) Now Initially, xcur = 2, so after 1st iteration, xnew = 2 - (-1)/2 = 2.5 Now xcur becomes 2.5, so after 2nd iteration, xnew = 2.5 - (0.25)/3 = 2.417 Happy Mittal answered Oct 28, 2014 • selected Oct 28, 2014 by Arjun Happy Mittal comment Share Follow See all 0 reply Please log in or register to add a comment.