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Given number is in octal (base 8)

Binary representation of given number is:

$(2357)^{_{8}} = (010 011 101 111)^{_{2}} \ \because \ 1 \ octal \ digit=3 \ binary \ digits \\ (0100 \ 1110 \ 1111)^{_{2}} = (4EF)^{_{16}} \ \because \ 4\ decimal \ digits = 1 \ hexadecimal\ digit$

**Hence option 3) is correct**

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2357 is given in octal

so its binary equivalent will be obtained by converting every number into 3-bit equivalent binary (010 011 101 111)

Now to convert this octal number into its equivalent hexadecimal number, pair 4 bits of above binary number starting from MSB

it will become (0100 1110 1111) which will be equivalent to 4EF

so, answer is C

so its binary equivalent will be obtained by converting every number into 3-bit equivalent binary (010 011 101 111)

Now to convert this octal number into its equivalent hexadecimal number, pair 4 bits of above binary number starting from MSB

it will become (0100 1110 1111) which will be equivalent to 4EF

so, answer is C