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Here $(2357)_8$ is an octal number representation in which each digit can be represented as $\log_28=3$ bit binary number.

To convert an octal number to a hexadecimal number, first, write its binary equivalent in the group of $3$ bit.

$(2357)_8=(\ 010 \ 011 \ 101 \ 111)_2$

Now we can rearrange this binary number into the group of $4$ bits to get the hexadecimal number. 

$(\ 010 \ 011 \ 101 \ 111)_2=( \ 0100 \ 1110 \ 1111)_H =(4EF)_H$

$\therefore (2357)_8=(4EF)_H$

Option $C$ is correct.

Gate 2004

Answer:

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