GIVEN
$F_{00} (0) = 1$,
$F_{00} (1) = 1$,
$F_{00}(n) = ((10 *F (n − 1) + 100)/F00 (n − 2)) for n \geqslant2$
Let n=2
$F_{00} (2) = (10 * F_{00} (1) + 100)/F_{00} (2-2)$
=$ (10 * 1 + 100)/1$
= $(10 + 100)/1$
=$110$
Let n=3
$F_{00} (3) = (10 * F_{00} (2) + 100)/F_{00} (3 - 2)$
= $(10 * 110 + 100)/1$
= $(1100 + 100)/1$
= $1200$
Similarly, n=4
$F_{ 00} (4) = (10 * F_{00} (3) + 100) /F_{00} (4- 2)$
=$10*1200+100/110$
= $(12100)/110$
=$110$
Similarly, n=5
$F 00 (5) = (10 * F00 (4) +100) /F00(5-2)$
= $(10*110 + 100) / 1200$
= $1200/1200$
=$1$
The sequence will be $(1, 110, 1200,110,1)$
0ption A