P is equivalent to Q means P is true, Q is true and P is false, Q is false.
If (R $\vee$ Q) is true and (P $\vee$ ~Q) is true then we can conclude that (P v R) is also true. (R $\vee$ Q) <==> (~R $\rightarrow$ Q) similarly (P $\vee$ ~Q) <==> (Q $\rightarrow$ P).
1. (~R $\rightarrow$ Q)
2. (Q $\rightarrow$ P)
$\therefore$ (~R $\rightarrow$ P) From 1 and 2 by applying Hypothetical syllogism.
(~R $\rightarrow$ P) <==> (R $\vee$ P).
So ((R∨Q)∧(P∨¬Q)∧(R∨P))((R∨Q)∧(P∨¬Q)∧(R∨P)) is true whenever ((R∨Q)∧(P∨¬Q)) is true
Also ((R∨Q)∧(P∨¬Q)∧(R∨P))((R∨Q)∧(P∨¬Q)∧(R∨P)) is false whenever ((R∨Q)∧(P∨¬Q)) is false.
So option B.