0 votes 0 votes Let $G(x)$ be generator polynomial used for CRC checking. The condition that should be satisfied by $G(x)$ to correct odd numbered error bits, will be: $(1+x)$ is factor of $G(x)$ $(1-x)$ is factor of $G(x)$ $(1+x^{2})$ is factor of $G(x)$ $x$ is factor of $G(x)$ Computer Networks ugcnetcse-jan2017-paper3 computer-networks crc-polynomial + – go_editor asked Mar 24, 2020 • recategorized May 24, 2020 go_editor 1.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply Rupendra Choudhary commented Oct 9, 2017 reply Follow Share https://gateoverflow.in/1334/gate2009-48 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes Ans will be A In this case polynomial generator should satisfy (A) Polynomial generated shouldn’t be divisible by x (B) It should be divisible by 1 + x i.e 1 + x is a factor of polynomial Sanjay Sharma answered Jan 28, 2017 Sanjay Sharma comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes A (1+x) is factor of G(x) Debasmita Bhoumik answered Feb 2, 2017 Debasmita Bhoumik comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes A) x+1 should be factor of G(x) Neeraj Chandrakar answered Oct 15, 2017 Neeraj Chandrakar comment Share Follow See all 0 reply Please log in or register to add a comment.