UGC NET CSE | December 2004 | Part 2 | Question: 11

Question

Suppose $x$ and $y$ are two Integer Variables having values $0\text{x5AB6}$ and $0\text{x61CD}$ respectively. The result (in hex) of applying bitwise operator and to $x$ and $y$ will be :

1. $0\text{x5089}$

2. $0\text{x4084}$

3. $0\text{x78A4}$

4. $0\text{x3AD1}$

Answer 1

$0\text{x5AB6}$ and $0\text{x61CD}$ are the hexadecimal representation of two integers and each hexadecimal digit can be represented by a $4-bit$ $(\log_2 16 = 4)$ binary number.

$0\text{x}$ is the prefix used to represent hexadecimal numbers in C.

$\frac{\begin{matrix} &5AB6 &=  &0101 &1010 &1011 &0110 \\ \& &61CD &= &0110 &0001  &1100  &1101 \end{matrix}} {\begin{matrix}  &4084 &= &0100  &0000  &1000  &0100\end{matrix}}$

Option $2$, $0\text{x4084}$ is correct.

Answer 2

$           $$5AB6$ $=$  $0101$  $1010$  $1011$  $0110$

 and $61CD$ $=$ $0110$  $0001$  $1100$  $1101$

                       $=$$0100$  $0000$  $1000$  $0100$ $=$ $4084$

Hence option B is the answer