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UGC NET CSE | December 2004 | Part 2 | Question: 8

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AND 

$(AB)C = A(BC) = ABC.$

OR

$(A + B) + C = A + (B + C)=A+B+C$

NAND

But, $((AB)′C)′ ≠ (A(BC)′)′ $does not follow associative property.

GATE1992-02-i - GATE Overflow

XOR

$ (a⊕b)⊕c=a⊕(b⊕c)$

 

 

 

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