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If $f (x)=x+1\:\text{and}\:g(x)=x+3$ then $f 0 f 0 f 0 f$  is :

1. $g$
2. $g+1$
3. $g^4$
4. None of these

$f of = (x+1)+1 = x+2$

$fo(f of) = (x+2)+1 = x+3$

$fo(fo(fof)) = (x+3)+1 = g + 1$

$(B)$ is the correct option.

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