UGC NET CSE | June 2005 | Part 2 | Question: 15

Question

Main()
{ char *str="abcde";
printf("%c",*str);
printf("%c",*str++);
printf("%c",*(str++));
printf("%s",str);
}

The output of the above $‘C’$ code will be :

• A. $\text{a a c b c d e}$
• B. $\text{a a c c c d e}$
• C. $\text{a a b c d e}$
• D. None of these

Answer 1

Correct ans is (C.): a a b c d e is the correct order of Output.

Take address of str =100.

Because in *str(*100) it will print "a" then, *str++ will print "a" again and increment str by 1(Now str is 101). It will print "b" and increment str by 1 again(Now str is 102). At last it will print whole string from *102 as format specifier is %s so c d e is printed.

Answer 2

the answer is $(D)$ output is $aabcde$

please add the missing printf statement in the code displayed after the question.

Comments

that option is actually $(C)$