recategorized by
407 views

2 Answers

0 votes
0 votes

Ans: C

x* y z* + x* y z + x y z* + x y z

  • x* y (z* + z) + x y (z* + z)
  • x* y + x y
  • y (x* + x)
  • y

 

0 votes
0 votes
The given logical expression can be reduces as follows:

$\implies \bar xy\bar z+\bar xyz+xy\bar z+xyz$

Taking common

$\implies \bar xy(z+\bar z)+xy(z+\bar z)$

$\because (x+\bar x=1)$

$\implies \bar xy+xy$

taking $y$ as common we get:

$\implies y(x+\bar x)$

$\implies y$

option C is correct.

Related questions

0 votes
0 votes
1 answer
1
go_editor asked Mar 26, 2020
329 views
Which of the following binary number is the same as its $2's$ complement :$1010$$0101$$1000$$1001$
0 votes
0 votes
1 answer
3
0 votes
0 votes
1 answer
4
go_editor asked Mar 26, 2020
1,258 views
The transitive closure of a relation $R$ on set $A$ whose relation matrix $\begin{bmatrix}0 & 1 & 0\\ 0 & 0 & 1 \\ 1 & 0 & 0\end{bmatrix}$ is :$\begin{bmatrix}0 & 1 & 0\\...