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UGC NET CSE | December 2006 | Part 2 | Question: 29

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The subnet mask 255. 255. 255. 192 in binary is 

11111111   11111111 11111111 11 000000

first 26 1's tells the network potion  and last 6  0's  host id part

so B is the ans

 

 

 

 

 

 

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2^6 is host id present on given sm so total number of host id is 6,nd we no IP is 32 bit so network id = ip-hostid

32-6=26 ans
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