0 votes 0 votes What is the maximum counting speed of a $4$-bit binary counter which is composed of Flip-Flop with a propagation delay of $25\:ns$? $1 \text{MHz}$ $10 \text{MHz}$ $100 \text{MHz}$ $4 \text{MHz}$ Others ugcnetcse-june2007-paper2 + – go_editor asked Mar 28, 2020 edited May 21, 2021 by soujanyareddy13 go_editor 1.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Question is about frequency of the counter. Frequency = 1/ Time Binary counter is ripple counter where the output one flip flop is clock input to next flip flop. So, maximum delay(time)= 4*25ns = 100 ns. frequency=1/100 ns = 10 MHz. Mohit Kumar 6 answered Jun 6, 2020 Mohit Kumar 6 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes (B) 10 MHz... 4 Bit binary counter(asynchronous counter) means.. There are 4 flip flops and each flip flop delay is 25ns … So total delay 4*25ns = 100ns … Counting speed = frequency of the output = 1/100 =10Mhz … Awe111 answered Nov 16, 2021 Awe111 comment Share Follow See all 0 reply Please log in or register to add a comment.