0 votes 0 votes The present ages of three persons in proportions $4:7:9$. Eight years ago, the sum of their ages was $56$. Find their present ages (in years). $8,20,28$ $16,28,36$ $20,35,45$ None of the above options Quantitative Aptitude nielit2017-scientistb-cs general-aptitude + – admin asked Mar 30, 2020 • edited Nov 6, 2020 by soujanyareddy13 admin 453 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Sum of age 8yrs ago was 56 Sum of age presently is 56+24 = 80 Ratio is 4:7:9 at present. 4x + 7x + 9x = 20x 20x = 80 => x = 4 So B is correct. smsubham answered Apr 2, 2020 smsubham comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Eight Years Ago the sum of their Ages was 56 so Present Sum would be (56+8+8+8)=80 . Now The Option Will be that which has sum of ages equal to 80 i.e. Option B gaurav1.yuva answered Mar 30, 2020 gaurav1.yuva comment Share Follow See all 0 reply Please log in or register to add a comment.
