4 votes 4 votes On a set $A = \{a,b,c,d\}$ a binary operation $*$ is defined as given in the following table. $$\begin{array}{|c|cccc|}\hline\text{*}&a&b&c&d\\\hline \text{a}&a&c&b&d\\\text{b}&c&b&d&a\\\text{c}&b&d&a&c\\\text{d}&d&a&c&b\\\hline \end{array}$$ The relation is Commutative but not associative Neither commutative nor associative Both commutative and associative Associative but not commutative Set Theory & Algebra nielit2017dec-scientistb discrete-mathematics group-theory abelian-group + – admin asked Mar 30, 2020 • retagged Oct 23, 2020 by Krithiga2101 admin 1.8k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
4 votes 4 votes Commutative but not associative ex.for associative a*(b*d) = a*a = a (a*b)*d =c*d =c pawan kumarln answered Dec 18, 2017 pawan kumarln comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes $A$ is correct. Work through some examples. Like $a*b=b*a=c$, $c*b=b*c=d$ and so on. It is not associative w.r.t this example: $(a*b)*c=c*c=a$ but $a*(b*c)=a*d=d$, which are not equal. haralk10 answered Mar 29, 2020 haralk10 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes (A) Commutative but not associative topper98 answered Mar 19, 2020 topper98 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes It is commutative but not associative. eshita1997 answered Jan 6, 2021 eshita1997 comment Share Follow See all 0 reply Please log in or register to add a comment.