let write a logic for "All my friends are perfect"

$\vee x(q(x)\rightarrow p(x))$

take negation of above "none of my friends are perfect"

$\sim(\vee x(q(x)\rightarrow p(x)))$

$\sim\vee x (\sim q(x)\vee p(x))))$

$Ǝx(q(x)\wedge \sim p(x))$

Correct me if I am wrong.