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In how many ways $8$ girls and $8$ boys can sit around a circular table so that no two boys sit together?

  1. $(7!)^2$
  2. $(8!)^2$
  3. $7!8!$
  4. $15!$
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1 Answer

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First arrange boys or girls on the circle

No of ways to arrange in nplaces around circle= (n-1)!

Here let say first we arrange boys in 8 places= (8-1)=7!

Now in the remaing 8 places we have to arrange girls= 8!

So total ways = 7! * 8!.

Answer:C

Answer:

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