Given let Let LOC of L1=x, so LOC of L2=2x
Now, for L1
man year needed for development = LOC/10000
development cost per man year=(LOC/10000)*1000000
maintenance time =5 year
cost of maintenance per year=100000
total maintenance cost=5*100000
total cost for L1=(x/10000)*1000000 + 5*100000 =100x+500000
now for L2
man year needed for development =LOC/10000
development cost per man year=(LOC/10000)*750000
maintenance time =5 year
cost of maintenance per year=50000
total maintenance cost=5*50000
Total cost for L2= (2x/10000)*750000 + 5*50000=150x+250000
if put x=5000 both give 1000000 same cost
Ans should be 5000 Option B