1 votes 1 votes Bandwidth of a link is 1000 Mbps and RTT is given as 250 micro seconds. If frame size is 500 bits. the utilization(in %age) of channel when stop and wait ARQ used is _________. Computer Networks computer-networks + – prathams asked Jan 3, 2016 prathams 1.1k views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply resuscitate commented Jan 3, 2016 reply Follow Share .2 ?? 1 votes 1 votes Prasanna commented Jan 3, 2016 reply Follow Share me too got 0.002 0 votes 0 votes fodu...todu commented Jan 3, 2016 reply Follow Share is ans 0.199 = 0.2 ? 0 votes 0 votes prathams commented Jan 3, 2016 reply Follow Share yes answer given is 0.2, can you post your calculation as answer here. 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes lu%=(TT/TT+2PT)*100 TT=data/ bandwidth =500/1000*106 =0.5 microsec RTT=250microsec so LU %=(0.5/0.5+250) =0.5/250.5 =0.00199 *100 =0.199 ≅0.2(ans) focus _GATE answered Jan 3, 2016 edited Jan 4, 2016 by focus _GATE focus _GATE comment Share Follow See all 2 Comments See all 2 2 Comments reply prathams commented Jan 3, 2016 reply Follow Share Is it a good practice to round off the answer when necessary, as answer given was 0.2 but answer comming close to 0.2 i.e., 0.199. 1 votes 1 votes Himanshu1 commented Jan 4, 2016 reply Follow Share I suggest to use RTT in place of TT + 2 PT when RTT given in Question. 0 votes 0 votes Please log in or register to add a comment.