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Bandwidth of a link is 1000 Mbps and RTT is given as 250 micro seconds. If frame size is 500 bits. the utilization(in %age) of channel when stop and wait ARQ used is _________.

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lu%=(TT/TT+2PT)*100
TT=data/ bandwidth
 =500/1000*106
 =0.5 microsec

 

RTT=250microsec
so LU %=(0.5/0.5+250)
             =0.5/250.5
             =0.00199 *100
             =0.199

            ≅0.2(ans)

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