1 votes 1 votes If every functional dependency in set $E$ is also in closure of $F$ then this is classified as $FD$ is covered by $E$ $E$ is covered by $F$ $F$ is covered by $E$ $F$ plus is covered by $E$ Databases nielit2016dec-scientistb-cs databases database-normalization + – admin asked Mar 31, 2020 • retagged Oct 22, 2020 by Krithiga2101 admin 1.7k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply s_dr_13 commented Apr 1, 2022 reply Follow Share Shouldn’t it be C ?? 0 votes 0 votes _Shubham_.Singh_ commented Aug 12, 2023 reply Follow Share No, coz F might have some extra FD's. 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes If every functional dependency in set E is also in closure of F means $F^{*}\subseteq E^{*}$ E cover F if every FD in F can be referred from E. E cover F if $ F^{*}\subseteq E^{*}$(* is clouser) so ans should be B E is covered by F Mohit Kumar 6 answered May 26, 2020 Mohit Kumar 6 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes ans : B If every functional dependency in set E is also in closure of F Then it means that E is covered by F anjli answered Feb 6, 2021 anjli comment Share Follow See all 0 reply Please log in or register to add a comment.