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NIELIT 2016 MAR Scientist B - Section B: 2

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The number of ways in which a team of eleven players can be selected from $22$ players including $2$ of them and excluding $4$ of them is 

  1. $^{16}\large_{C_{11}}$
  2. $^{16}\large_{C_{5}}$
  3. $^{16}\large_{C_{9}}$
  4. $^{20}\large_{C_{9}}$
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it will be 16 C 9 as the two players are always in the team and four are excluded from the team.

Hence total choices are from 22-2-4=16.

again we have to choose 11-2 =9 from these 16 alyers .

hence the no of ways 16C9.

Hence the option C is correct.
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