recategorized by
796 views
3 votes
3 votes

A polynomial $p(x)$ is such that $p(0)=5, \: p(1)=4, \: p(2)=9$ and $p(3)=20$. The minimum degree it can have is

  1. $1$
  2. $2$
  3. $3$
  4. $4$
recategorized by

1 Answer

1 votes
1 votes
We have 4 equations. Using them we can determine at least 4 variable. Hence the equation will be ax^3+bx^2+cx+d=0

Therefore the minimum degree will be 3.
Answer:

Related questions

1 votes
1 votes
0 answers
1
admin asked Mar 31, 2020
454 views
If $\Delta f(x)= f(x+h)-f(x)$, then a constant $k,\Delta k$$1$$0$$f(k)-f(0)$$f(x+k)-f(x)$
2 votes
2 votes
1 answer
2
admin asked Mar 31, 2020
712 views
What is the determinant of the matrix $\begin{bmatrix}5&3&2\\1&2&6\\3&5&10\end{bmatrix}$$-76$$-28$$+28$$+72$
3 votes
3 votes
2 answers
3
admin asked Mar 31, 2020
664 views
The greatest and the least value of $f(x)=x^4-8x^3+22x^2-24x+1$ in $[0,2]$ are$0,8$$0,-8$$1,8$$1,-8$
4 votes
4 votes
1 answer
4
admin asked Mar 31, 2020
717 views
The system of simultaneous equations$x+2y+z=6\\2x+y+2z=6\\x+y+z=5$hasunique solution.infinite number of solutions.no solution.exactly two solutions.