NIELIT 2017 DEC Scientific Assistant A - Section B: 42

Question

Which of the following is illegal declaration in $C$ language?

• A.

  char*str ="Raj is a Research scholar";
  

• B.

  char str[25] ="Raj is a Research scholar";
  

• C.

  char str[40] ="Raj is a Research scholar";
  

• D.

  char[]str ="Raj is a Research scholar";

   

Answer 1

Ans initialization  of variable in Option D not valid

Character array/ string initialization:
char variable_name[]= "India";   
OR
char variable_name[10]= "India"; 

option B,D let str[25} an char array and starting address of array is 1000

R

a

j

i

s

a

r

e

a

r

c

h

s

c

h

o

l

a

r

/0

/0

in Option A  str is char pointer which pointing or store starting address of char array

str

1000

 

Comments

whats the difference between options B and C?

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@gatecse only the size of array is different (25 vs 40).

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There is a spelling mistake in the answer. If corrected we can see that the given string does not fit in 25 characters or does it?

---

The compiler will not throw any error or warning, but since there is no space left for ‘\0’, you’ll see some garbage value after “scholar”.

Answer 2

corect option is d

char[]str ="Raj is a Research scholar";it is not a valid declaration in c language .