1 votes 1 votes $\left (0+ \varepsilon \right) \left (1+ \varepsilon \right)$ represents : $\left \{0,1,01,\varepsilon \right \}$ $\left \{0,1,\varepsilon \right \}$ $\left \{0,1,01, 11, 00 ,10,\varepsilon \right \}$ $\left \{0,1, \right \}$ Theory of Computation nielit2017dec-assistanta theory-of-computation regular-expression + – admin asked Mar 31, 2020 recategorized Aug 24, 2020 by Lakshman Bhaiya admin 938 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Sanandan commented Sep 1, 2020 reply Follow Share option A 0 votes 0 votes Rishabh Mondal commented Nov 17, 2020 reply Follow Share can anyone draw the state diagram of that expression. 0 votes 0 votes chinmayc commented Nov 13, 2021 reply Follow Share Option A is correct 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes $\epsilon.SOMETHING=SOMETHING$ $\epsilon.\epsilon=\epsilon$ OPTION A $(0+\epsilon)(1+\epsilon)$ = $0.1+0.\epsilon+\epsilon.1+\epsilon\epsilon$ = $01,0,1,\epsilon$ = $\left \{ 0,1,O1,\epsilon \right \}$ Mohit Kumar 6 answered May 20, 2020 Mohit Kumar 6 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes so option A is correct Ram13may answered Jan 3, 2021 Ram13may comment Share Follow See all 0 reply Please log in or register to add a comment.