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Disk request come to a disk driver for cylinders in the order $10,22,20,2,40,6$ and $38,$ at a time when the disk drive is reading from cylinder $20$. The seek time is $6\text{ ms}$ per cylinder. The total seek time, if the disk arm scheduling algorithm is first-come-first-served is

  1. $900$ ms
  2. $850$ ms
  3. $360$ ms
  4. $876$ ms
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AND IS D

1. FCFS
Total seek time
= 10*6 + 12*6 + 2*6 + 18*6+ 38 * 6 + 34*6 + 32*6
= 146*6
= 876 ms

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Ans : 146

 FCFS

Head start from 20

20 ->10->22->20->2->40->6->38
Total seek time
= 10 + 12 + 2+ 18+ 38  + 34 + 32
= 146
Answer:

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