retagged by
1,464 views

2 Answers

5 votes
5 votes

$\left | k\times A_{n\times n} \right |=k^{n}\times\left | A_{n\times n} \right |$  (Reference: Determinant when multiplying a matrix by a constant)

$\therefore$ Let the original value of determinant be  $\Delta$  i.e.  $\Delta=5$

When each element of the matrix is multiplied by $2$, the resultant determinant becomes $40$

$\therefore$  $2^{n}\times 5=40 \Rightarrow 2^{n}=8 \Rightarrow n=3$

Option B is correct.

Answer:

Related questions

0 votes
0 votes
1 answer
1
admin asked Apr 1, 2020
596 views
$M$ is a square matrix of order $’n’$ and its determinant value is $5.$ If all the elements of $M$ are multiplied by $2,$ its determinant value becomes $40.$ The valu...
1 votes
1 votes
2 answers
2
admin asked Apr 1, 2020
1,608 views
If $P$ is risk probability, $L$ is loss, then Risk Exposure $(RE)$ is computed as.$RE = P/L$ $RE = P + L$$RE = P \ast L$$RE = 2 \ast P \ast L$
2 votes
2 votes
1 answer
3
admin asked Apr 1, 2020
643 views
What is the maximum value of the function $f(x) = 2x^{2} – 2x + 6$ in the interval $[0,2]?$$6$$10$$12$$5,5$
0 votes
0 votes
1 answer
4
admin asked Apr 1, 2020
475 views
The value of the Integral $I = \displaystyle{}\int_{0}^{\pi/2} x^{2}\sin x dx$ is$(x+2)/2$$2/(\pi-2)$$\pi – 2$$\pi + 2$