Here, Instruction format =10bits
Size of address field= 3bit
For two address field
Op code=4bit |
add1= 3bit |
add2= 3bit |
Uses 4 two address instructions
Remaining= 2^4 - 4=12
For One address instruction
Uses 16 one address instruction
Remaining= 12 *2^3 -16
=12*8 -16
= 80
For zero address instruction
80*2^3 =640
Option C