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The number of columns in a state table for a sequential circuit with $’m’$ flip flops and $’n’$ input is

1. $m+n$
2. $m+2n$
3. $2m+n$
4. $2m+2n$

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I think state table mean, the information about inputs and on seeing what inputs, we can know about the states of the flip-flop, in the sense what is the present and next state of the flip-flop.

So, for each of any of the M flip-flops, we have to write the present as the next state of the flip-flop.

hence for M=1, we should have two entries, one for present state and one for next state.

So, for M flip-flops, there will be 2M columns for flip-flop state information.

If there is one input,  then there will be 1 column.

so for N input, we should have N columns.

so, total columns in state table = 2M + N

so correct option is C...
As explained by akash.dinkar, I also feel that 2M+N should be correct answer. What is correct answer?
yes correct ans is 2M+N

akash convert ur comment into ans

I think state table mean, the information about inputs and on seeing what inputs, we can know about the states of the flip-flop, in the sense what is the present and next state of the flip-flop.

So, for each of any of the M flip-flops, we have to write the present as the next state of the flip-flop.

hence for M=1, we should have two entries, one for present state and one for next state.

So, for M flip-flops, there will be 2M columns for flip-flop state information.

If there is one input,  then there will be 1 column.

so for N input, we should have N columns.

so, total columns in state table = 2M + N

so correct option is C...
its 2m+2n because..
If there are m flip-flops, there should be 2m nodes. If there are n inputs, then each node will have 2n

### 1 comment

@pawan

can u explain with examples???

Option (C). 2m+n

m columns for present states

m columns for next states

n columns for input values

Total : m+m+n = 2m+n

https://gateoverflow.in/130150/number-columns-state-table-sequential-circuit-flops-input

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