Maximum number of bps = B log (1 + SNR).

=3000*log(1+30)

=3000*4.95

=14850. So approximately, 15000

Logarithm is in "Base 2".

=3000*log(1+30)

=3000*4.95

=14850. So approximately, 15000

Logarithm is in "Base 2".

0 votes

The maximum data rate of a channel of $3000$-Hz bandwidth and SNR of $30$ db is

- $60000$
- $15000$
- $30000$
- $3000$