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Consider a system having $’m’$ resources of the same type. These resources are shared by $3$ processes $A,B,C;$ which have peak time demands of $3,4,6$ respectively. The minimum value of $’m’$ that ensures that deadlock will never occur is

1. $11$
2. $12$
3. $13$
4. $14$

### 1 comment

A) 11

2+3+5+1=11

we need 11 resources fo dead lock free

Ans should be A

SO ANS IS: A

DEADLOCK WILL NOT HAPPEN AFTER 11 AND HIGHER THAN 11 VALUE.

SO ANS IS 11

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