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If the channel is band limited to $6\;kHz$ and signal to noise ratio is $16,$ what would be the capacity of channel?

  1. $16.15$ kbps
  2. $23.24$ kbps
  3. $40.12$ kbps
  4. $24.74$ kbps
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Option D as per Shannon formula which state that the capacity of a channel with B.W = B and Signal to Noise ratio is S/ N, then Capacity C= B Log ( 1+S/N) ,the base of logarithm is 2.

Here putting the value B= 6 KHz, S/ N=16 we get Capacity is approx ..24.78 Kbps.
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