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NIELIT 2016 MAR Scientist C - Section C: 63

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3 Answers

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With n bit numbers possible is = $2^n$ 

so here n=8 therefore number possible is $2^8$ = 256 

now for unsigned number range would be 0 to 255

and for signed number range would be -128 to 127 (Keeping in mind that 0 has two representation)

so answer would be option A

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