1 votes 1 votes How many bits are required to encode all twenty six letters, ten symbols, and ten numerals? $5$ $6$ $7$ $46$ Computer Networks nielit2016mar-scientistc computer-networks network-security + – admin asked Apr 2, 2020 • recategorized Oct 28, 2020 by Krithiga2101 admin 772 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes 26 letters + 10 symbols + 10 numerals = 46 any binary code is represented in powers of 2 5 BIT=2^5=32 6 BIT=2 ^6 =64 7 BIT=2^7=128 In 6 bit is sufficient we can can represent the 46 thing uniquely.. option should be B. Mohit Kumar 6 answered May 3, 2020 Mohit Kumar 6 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes In 6 bit is sufficient we can can represent the 46 thing uniquely.. option -- B heisenberggg answered Apr 5, 2021 heisenberggg comment Share Follow See all 0 reply Please log in or register to add a comment.