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The coefficient of x^k is given as after solving:

(-1)^(100-((k+100)/3)) * 100C((k+100)/3)

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admin asked Apr 30, 2020
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Show that if $n$ and $k$ are integers with $1 \leq k \leq n,$ then $\binom{n}{k} \leq \frac{n^{k}}{2^{k−1}}.$