Using Pascal’s identity C(n, k) + C(n, k + 1) = C(n + 1, k + 1) and the identities C(n, 0) = C(n, n) = 1,
we obtain the row C(11, 0) C(11, 1) . . . C(11, 7) C(11, 8) C(11, 9) C(11, 10) C(11, 11)
in the Pascal triangle from the given row: 1 11 55 165 330 462 462 330 165 55 11 1.