0 votes 0 votes if 50 stations are there and if each slot contain 25 microsec then what would be max waiting time for a station for safe transmission a)200 b)300 c)250 d)400 komal07 asked Jan 4, 2016 komal07 1.0k views answer comment Share Follow See 1 comment See all 1 1 comment reply set2018 commented Oct 28, 2017 reply Follow Share why are you taking 10? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes In binary exponential backoff, the threshold or limit of collision is upto 10 collision. as each slot contain 25 microsec. max waiting time 250 microsec. resuscitate answered Jan 4, 2016 resuscitate comment Share Follow See all 4 Comments See all 4 4 Comments reply komal07 commented Jan 4, 2016 reply Follow Share https://en.m.wikipedia.org/wiki/Exponential_backoff Here Max no of transmission attempt is written as 16 But won't we multiply slot time by 2^16 -1 .. (since random no is chosen from 0 to 2^16-1) 0 votes 0 votes resuscitate commented Jan 4, 2016 i edited by resuscitate Jan 4, 2016 reply Follow Share yes but threshold is 10. u can check it..and uu can choose random no upto 2^10-1= 1023.not 2^16 -1 0 votes 0 votes komal07 commented Jan 5, 2016 reply Follow Share can you please share source. 0 votes 0 votes resuscitate commented Jan 5, 2016 reply Follow Share The 'truncated' simply means that after a certain number of increases, the exponentiation stops; i.e. the retransmission timeout reaches a ceiling, and thereafter does not increase any further. For example, if the ceiling is set at i = 10 (as it is in the IEEE 802.3 CSMA/CD standard[1]), then the maximum delay is 1023 slot times. from wiki.... https://en.wikipedia.org/wiki/Exponential_backoff#Binary exponential backoff 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes maximum waiting time in backoff algo is up to 16 collision 25*16=400 answer is 400 microsec Mohitdas answered May 20, 2020 Mohitdas comment Share Follow See all 0 reply Please log in or register to add a comment.
