TCP Congestion Control

Question

Comments

4 to 8 one rtt. now u can count.. 4-8-16-32-4-8-16-20-24-28-32.now count the dash..rtt = 10

---

okk ... why u counted RTT before timeout???????

and one more thing there solution started mss from 1-2- and then 4 it was wrong  na???

---

thres=32/4=8kb

4-8---(thres reached so addaptive increase)----12-16-20-24-28-32

rrt=7

100*7=700

Answer 1

Question is wrong as well as the answer markeed by pooja  ,.(i guess)
time out at 32 KB

(before timeout scenarioo should not be considered here)

then after time out it will be like 4-8-16--20--24--28--32

6RTT

6*50=300ms

300ms should be correct answer

Comments

Yes correct...

Answer 2

4---8---16---32 ---now time out---4---8---16(additive increase) ---20----24---28----32

 

so  congestion window =16

10 RTT

so 10*50=500

Comments

I​t should be 300 msec.

---

 Amar Sir .......Yess.....

Question was wrong...If It was 100 msec then ans was 600 as options but they have given 50 and there is no option for this...So i got this.....

But i dnt understood why @Pooja is counting from Beginning ie.,, 4---8---16---32 ---now time out---4---8---16(additive increase) ---20----24---28----32

before timeout why we will count???????

But Still I got the concept ans is 300...I AM ATTACHING REFERENCE:

https://gateoverflow.in/1794/gateoverflow.in

best solution :) to understand this concept

4----8---`16----20---24----28-----32

---

can u please explain this question:

https://gateoverflow.in/76084/made-easy-test-series-2016-tcp-congestion-control 

a/c to above concept its answer should be 60msec by counting vertical bars but ans is 70msec

Answer 3

TH=32/2=16

4 8 16 20 24 28 32

Total time to reach at 32kb=6*50ms=300ms

Answer 4

Answer is 300

4kb-8kb-16kb-20kb-24kb-32kb

Total RTT=6

I e 6 *50ms =300ms