Given that,
- $a:b = 1:3\qquad \rightarrow(1)$
- $b:c = 6: 20 \qquad \rightarrow(2)$
- $c:d = 5:2\qquad \rightarrow(3)$
- $d:e = 4:5\qquad \rightarrow (4)$
From equations $(1),(2)$ we get
- $a:b:c = 1:3:10 \qquad \rightarrow (5)$
From equations $(5),(3),(4)$ we get
- $a:b:c:d:e = 1:3:10:4:5\qquad \rightarrow (6)$
Taking the proportionality constant as $k,$ we get $a = k,b = 3k,c = 10k,d = 4k,e = 5k$
$\therefore \dfrac{ed + bc}{cd + ab} = \dfrac{20k^{2} + 30k^{2}}{40k^{2} + 3k^{2}} = \dfrac{50k^{2}}{43k^{2}} = \dfrac{50}{43}.$
So, the correct answer is $(B).$