87 views
1 votes
1 votes

If $x = 3\, \dfrac{1}{3} + 4\, \dfrac{1}{5} + 5\, \dfrac{1}{7} + 7\, \dfrac{1}{2},\,\text{and}\, y = 5\, \dfrac{3}{7} - 4\, \dfrac{1}{5} - 5\, \dfrac{1}{7} - 7\, \dfrac{1}{2},$ then the value of $x + y = $ ________
 

  1. $\dfrac{184}{21}$
  2. $\dfrac{114}{21}$
  3. $\dfrac{174}{21}$
  4. $\dfrac{21}{184}$

1 Answer

2 votes
2 votes
We can add all the fractions and get,
  
  $x + y = 3\, \dfrac{1}{3} + 4\, \dfrac{1}{5} + 5\, \dfrac{1}{7} + 7\, \dfrac{1}{2} + 5\, \dfrac{3}{7} - 4\, \dfrac{1}{5} - 5\, \dfrac{1}{7} - 7\, \dfrac{1}{2}$
    
 $\implies x + y = 3\, \dfrac{1}{3} + 5\, \dfrac{3}{7}$
    
 $\implies x + y = \dfrac{184}{21}.$   
     
 So, the correct answer is $(A).$
Answer:

Related questions

2 votes
2 votes
1 answer
1
3 votes
3 votes
1 answer
2
Arjun asked Jun 12, 2021
214 views
The polynomial $x^{4} - ax^{3} + bx^{2} - cx + 4$ when divided by $x - 1$ leaves a remainder of $7$ and when divided by $x + 1$ leaves a remainder $9.$ Then $b^{2} = $___...
1 votes
1 votes
1 answer
4
Arjun asked Jun 12, 2021
120 views
If the area of a square is increased $44\%$ percent, what will be the percentage increase in its perimeter?$5\%$$8\%$$20\%$$22\%$