If the angle $\theta$ is in degrees, then the area of sector is $\dfrac{\theta}{360^{\circ}}$
of the circle. Since the area of the circle is $\pi r^{2},$ the area of sector is
$\dfrac{\theta}{360^{\circ}} \times \pi r^2.$
If $\theta$ is in radians, then the area of sector is $\dfrac{\theta}{2\pi}$ of the circle, and hence the area of sector is $\dfrac{\theta}{2\pi} \times \pi r^2 =\dfrac{1}{2} r^2 \theta.$
Given that, sector radius $r = 17\,\text{cm}$
Required area $A = \dfrac{\theta}{360^{\circ}} \times \pi r^{2}$
$\implies A = \dfrac{30^{\circ}}{360^{\circ}} \times \pi \times 17^{2}$
$\implies A = \dfrac{\pi \times 289}{12}$
$\implies A = 75.66\,\text{cm}^{2}.$
So, the correct answer is $(A).$