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GATE Overflow Test Series | Quantitative Aptitude | Test 1 | Question: 3

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3 Answers

5 votes
5 votes
We know that, $49$ is divisible by $7,$ so it will give remainder $=0$ when divided by $0$ and so do any power of $49.$ So, any power of $49$ minus $1$ will be $1$ less than a multiple of $7$ or will give $7-1 = 6$ as remainder when divided by $7.$

So, the correct answer is $(B).$
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3 votes
3 votes
(49)^(bla...bla) = (7)^(2*bla...bla...).

Also 7*x – 1 will always give a remainder of 6

So, 6 is answer.
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0 votes
0 votes
It is 49^2021! = 7 ^ 2*2021!

One thing to note that 7*(n) – 1 will give remainder 6,  eg put n = 1,2,3…..

So ans here will be 6.
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