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GATE Overflow Test Series | Quantitative Aptitude | Test 1 | Question: 2

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$\text{Speed(S)} = \dfrac{\text{Distance(D)}}{\text{Time(T)}}$
 
 $\implies S \propto D$
 
 $\implies S_{1}:S_{2} = D_{1}:D_{2}$
 
 Let actual distance travelled by a person $k\,km.$
 
 $\implies 20:24 = k : (k + 40)$
 
 $\implies 5:6 = k : (k + 40)$
 
 $\implies \dfrac{k}{k + 40} = \dfrac{5}{6}$
 
 $\implies k = 200\,km.$
 
 $$\textbf{(OR)}$$
 
 Difference of the speed's$ = 24 - 20 = 4\,km/hr$
 
 $\implies 4\,km/hr\longrightarrow 40\,km$
 
  $\implies 20\,km/hr\longrightarrow \dfrac{40}{4}\times 20\,km = 200\,km$
 
 So, the correct answer is $(C).$
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Let,

for speed 20km/hr,  dis = x km

so for speed 24km/hr, dis = x+40 km

5/6 = x/x+40

x = 200 km.
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