"There is a student who is loved by every other student."
Here, $\text{Loves}(p,q)$ means $p \text{ loves}\; q.$
We can interpret in this way,
- $\text{Raju}$ is loved by $\text{Rani}$
- $\text{Raju}$ is loved by $\text{Vani}$
- $\text{Raju}$ is loved by $\text{Rakesh}$
- $\text{Raju}$ is loved by $\text{Suresh}$
- and, so on..
In other way,
- $\text{Rani}$ loves $\text{Raju}$
- $\text{Vani}$ loves $\text{Raju}$
- $\text{Rakesh}$ loves $\text{Raju}$
- $\text{Suresh}$ loves $\text{Raju}$
- But, Raju cannot loves himself.
Similarly, we can write like this,
- $\text{Loves(Rani,Raju)}$
- $\text{Loves(Vani,Raju)}$
- $\text{Loves(Rakesh,Raju)}$
- $\text{Loves(Suresh,Raju)}$
Now, Lets take $\text{Student}(x):x$ is a student$,\text{Student}(y):y$ is a student.
Domain of discourse:All the people
- There is a student $x,$ who loved by student $y_{1}$
- There is a student $x,$ who loved by student $y_{2}$
- There is a student $x,$ who loved by student $y_{3}$
- ----------------------------------------------------------------------
- There is a student $x,$ who loved by student $y_{n}$
Now, we can represent above statements in this way,
- $y_{1} \;\text{loves} \;x$
- $y_{2} \;\text{loves} \;x$
- $y_{3} \;\text{loves} \;x$
- -------------------------------
- $y_{n} \;\text{loves} \;x$
We can write above statements, like this
- $\text{Loves}(y_{1},x)$
- $\text{Loves}(y_{2},x)$
- $\text{Loves}(y_{3},x)$
- ------------------------------
- $\text{Loves}(y_{n},x)$
Now, write above statements in proper way,
There exist at-least one student $x,$ who loved by $y,$ if $y$ is a student, and $x$ can not loved by himself
$\exists x(\text{Student}(x) \wedge \forall y(\text{Student}(y) \wedge \neg(y=x) \rightarrow \text{Loves}(y,x)))$
So, the correct answer is $(B).$