This is a balls-in-bins problem with balls being identical and no bins being empty. This problem can be reduced to the integer sum problem
$x_1+x_2+x_3+x_4 = 10, x_i > 0$
This is same as
$x_1+x_2+x_3+x_4 = 6, x_i \geq 0$
(we allotted $1$ server to each laboratory)
Now, the above problem can be solved by putting $3$ separations among $6$ identical objects and then considering all the permutations as follows:
$******|||$
The three $|$ represent the $4$ regions corresponding to the $4$ bins. In the above representation (stars-and-bars), first bin is having the $6$ balls and the rest of the bins are empty. Now, the total number of permutations of the above (total $9$ objects where $6$ are of one kind and $3$ are of other) is
$\frac{9!}{6!.3!} = 84.$