This is a balls-in-bins problem where both balls and bins are distinct and no bin should be empty. If bins can be empty, the solution is given by $4\times 4 \times 4\times 4\times 4\times 4 = 4^6$ as each of the $6$ property can go to any of the $4$ daughters. Now from this we have to subtract the cases where some daughters are not getting any property which can be done by Inclusion-Exclusion Principle as follows:
First we will subtract (exclude) the cases where one daughter is not getting any property. Then we will add (include) the cases where 2 daughters are not getting any property (this was already subtracted in the earlier case). Then we will again subtract (exclude) the cases where 3 daughters are not getting any property. Now we are done as there is no option of $4$ daughters not getting any property.
So, our required answer $ = 4^6 - {}^4C_1 \times 3^6 +{}^4C_2 \times 2^6 - {}^4C_3 \times 1^6 $
$\qquad = 2^{12} - 4 \times 729 + 6 \times 64 - 4$
$\qquad =4096 - 2916 + 384 - 4$
$\quad = 1560.$