Given that $f(x)=5x+2$ and $g(x)=3x-4$
Inverse of the function $: f^{-1}(x)=\dfrac{x-2}{5}$ and $: g^{-1}(x)=\dfrac{x+4}{3}$
Now, $(f\circ g^{-1}\circ f^{-1})(a) = f(g^{-1}(f^{-1}(a)))=f\left(g^{-1}\left(\dfrac{a-2}{5}\right)\right)$
$= f\left(\dfrac{\dfrac{a-2}{5} + 4}{3}\right) = f\left(\dfrac{a+18}{15}\right)$
$= 5 \times \left(\dfrac{a+18}{15}\right) + 2 = \dfrac{a+24}{3}$
$ \dfrac{a+24}{3} = 4$
$\implies a=-12$
So, the correct answer is $-12$.