Simplify given switching network

Question

Comments

i think the correct answer will be  A*(B+C).D(P+P').

i.e ABD+ACD.

Answer 1

There is ambiguity in the diagram.

 

If you see switch D, does the box surrounding it part of circuit ? or just to represent D. If it is part of circuit, then D is not at all required. Current will flow towards both $P$ and $\bar{P}$

So it becomes $A.(B+C).(P+\bar{P})$ and we know if $P$ is closed, $\bar{P}$ will be open, both are compliments.

Final answer will be $AB+BC$

 

Now, lets say for sake of ambiguity, if switch D is mandatory and required to reach the other side, then

$A.(B+C).(DP+D\bar{P})$ because it will depend on switch D which path you take.

Final Answer will be $ABD +ACD$

 

In both cases, Answers does not match.

Answer 2

i am getting ABD'+ACD'.

A(B+C)D'(P+P')

Comments

Sir i how u got D'(complement of D)?

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How did you get complement of D?

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i think it should be only D

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Sir how u got D's Complement