2 votes 2 votes The implicants being chosen for the circuit implementation are marked in the following four Karnaugh-maps. In which of them, a static-$1$ hazard is not possible? Digital Logic go2025-digital-logic-1 k-map static-hazard + – gatecse asked Jul 19, 2020 • edited Jul 19, 2020 by Lakshman Bhaiya gatecse 430 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 4 votes 4 votes We avoid a static-1 hazard if every adjacent $1s$ in K-map is covered by an implicant. In Option A, this is TRUE. In all other options, at least $2$ adjacent $1s$ are there which are not being covered by an implicant. Reference: https://gateoverflow.in/1814/gate2006-38 gatecse answered Jul 19, 2020 • selected Jul 17, 2021 by Arjun gatecse comment Share Follow See all 3 Comments See all 3 3 Comments reply Rajat Maheshwari commented Jul 20, 2020 reply Follow Share So here, all have static hazards? 0 votes 0 votes mohitp commented Jul 21, 2020 reply Follow Share Option A does not have any static hazard as every two adjacent 1's are grouped or covered by a common implicant 2 votes 2 votes gatecse commented Jul 21, 2020 reply Follow Share Yes, no static hazard-1 for option A. 0 votes 0 votes Please log in or register to add a comment.