1 votes 1 votes If the number of prime implicants and essential prime implicants of $F(A,B,C,D) = \sum(0,6,8,13,14)$ are represented by $m$ and $n$ respectively, the value of $2^m\times 3^n = $ Digital Logic go2025-digital-logic-1 numerical-answers prime-implicants k-map min-sum-of-products-form + – gatecse asked Jul 19, 2020 gatecse 320 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes We have $3$ prime-implicants and all of them are essential as we don't have any alternative selection for any of them covering all $1s$ in the K-map. So, $m = n = 3.$ $\therefore 2^m \times 3^n = 2^3 \times 3^3 = 8 \times 27 = 216.$ gatecse answered Jul 19, 2020 • selected Jul 17, 2021 by Arjun gatecse comment Share Follow See all 2 Comments See all 2 2 Comments reply mrinmoyh commented Dec 7, 2020 reply Follow Share 13 is prime implicant or only implicant ?? @gatecse 0 votes 0 votes rupesh17 commented Jan 22, 2021 reply Follow Share mrinmoyh it is both prime implicant since it cannot be cover by bigger size and also it is essential prime implicant since it is not cover by any other prime implicant 0 votes 0 votes Please log in or register to add a comment.
